What is the derivative of e^{x{z}(x}) ?

The derivative of e^{x{z}(x}) is e^{x{z}(x)}({z}(x)+x derivative of {z}(x))

What is the first derivative of e^{x{z}(x}) ?

The first derivative of e^{x{z}(x}) is e^{x{z}(x)}({z}(x)+x derivative of {z}(x))

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\frac{d}{d x} (e^{x z (x)})

e^{x z (x)} (z (x) + x \frac{d}{d x} (z (x)))

Solution steps

\frac{d}{d x} (e^{x z (x)})

Apply the chain rule:

e^{x z (x)} \frac{d}{d x} (x z (x))

= e^{x z (x)} \frac{d}{d x} (x z (x))

\frac{d}{d x} (x z (x)) = z (x) + x \frac{d}{d x} (z (x))

= e^{x z (x)} (z (x) + x \frac{d}{d x} (z (x)))

t an g e n t f (x) = x^{2} + 169 x + 820, at x = 2

d er i v a t i v e y = \frac{2 x}{7 - cot ( x )}

\int (x^{- \frac{1}{2}}) d x

\int_{1}^{9} (x) d x

\int 49 d x

What is the derivative of e^{x{z}(x}) ?
The derivative of e^{x{z}(x}) is e^{x{z}(x)}({z}(x)+x derivative of {z}(x))
What is the first derivative of e^{x{z}(x}) ?
The first derivative of e^{x{z}(x}) is e^{x{z}(x)}({z}(x)+x derivative of {z}(x))