integral from-1 to 5 of |2x-3|

Lösung

\int_{- 1}^{5} ∣ 2 x - 3 ∣ d x

\frac{37}{2}

Dezimale

18.5

Schritte zur Lösung

\int_{- 1}^{5} ∣ 2 x - 3 ∣ d x

Entferne die Extremwerte

= \int_{- 1}^{\frac{3}{2}} - 2 x + 3 d x + \int_{\frac{3}{2}}^{5} 2 x - 3 d x

\int_{- 1}^{\frac{3}{2}} - 2 x + 3 d x = \frac{25}{4}

\int_{\frac{3}{2}}^{5} 2 x - 3 d x = \frac{49}{4}

= \frac{25}{4} + \frac{49}{4}

Vereinfache

\frac{25}{4} + \frac{49}{4} : \frac{37}{2}

= \frac{37}{2}

in v erse l a pl a ce - \frac{2 s + 1}{s ^{2} + 3 s + 2}

\frac{\partial}{\partial y} (x^{3} y^{6})

\int (3 x^{- 2} - 4 x^{2} + 1) d x

\frac{\partial}{\partial x} (e^{- 9 x} cos (θ))

in v erse l a pl a ce \frac{s}{s ^{2} + 4 ^{2}}