derivative of sqrt(3)cos(4x+sin(4x))

解答

\frac{d}{d x} (3 cos (4 x) + sin (4 x))

- 43 sin (4 x) + cos (4 x) \cdot 4

求解步骤

\frac{d}{d x} (3 cos (4 x) + sin (4 x))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 cos (4 x)) + \frac{d}{d x} (sin (4 x))

\frac{d}{d x} (3 cos (4 x)) = - 43 sin (4 x)

\frac{d}{d x} (sin (4 x)) = cos (4 x) \cdot 4

= - 43 sin (4 x) + cos (4 x) \cdot 4

a re a x = 1, x = 3, y = x^{3} - 8, y = 0

l a pl a ce t r an s f or m 2 (t - 3)^{2} + 15 (t - 3) + 26

\frac{d}{d x} (\frac{8 ( 4 ^{x} )}{x ^{4}})

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