derivative of y^2+x^2-2

解答

\frac{d}{d x} (y^{2} + x^{2} - 2)

2 x + 2 y \frac{d y}{d x}

求解步骤

\frac{d}{d x} (y^{2} + x^{2} - 2)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{2}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2)

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2) = 0

= 2 y \frac{d y}{d x} + 2 x - 0

化简

= 2 x + 2 y \frac{d y}{d x}

\int a - x^{2} d x

n = 1 \sum \infty \frac{1}{3 n - 2}

d er i v a t i v e f (x) = 6 x^{l n (x)}

d er i v a t i v e - \frac{5}{x ^{3}}

d er i v a t i v e f (x) = 3 x + 5