integral from-2 to 1 of 1/(sqrt(2-x))

Lösung

\int_{- 2}^{1} \frac{1}{2 - x} d x

2

Schritte zur Lösung

\int_{- 2}^{1} \frac{1}{2 - x} d x

Wende U-Substitution an

= \int_{4}^{1} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{4} - \frac{1}{u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{1}^{4} \frac{1}{u} d u)

Wende die Potenzregel an

= - (- [2 u^{\frac{1}{2}}]_{1}^{4})

Vereinfache

- (- [2 u^{\frac{1}{2}}]_{1}^{4}) : [2 u]_{1}^{4}

= [2 u]_{1}^{4}

Berechne die Grenzen:

2

= 2

\frac{d}{d x} (x e^{- 6 x})

k = 2 \sum \infty \frac{3}{2 ^{k}}

\frac{\partial}{\partial y} (e^{2 x - 3 y})

\frac{\partial}{\partial x} (y^{2} + x)

\frac{d}{d x} (sin (5))