What is the solution for (dy)/(dx)(xsqrt(16-x))=0 ?

The solution for (dy)/(dx)(xsqrt(16-x))=0 is y=c_{1}

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(dy)/(dx)(xsqrt(16-x))=0

\frac{d y}{d x} (x 16 - x) = 0

y = c_{1}

Solution steps

\frac{d y}{d x} (x 16 - x) = 0

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) (x 16 - x) = 0

Isolate

y^{'} (x) : y^{'} (x) = 0

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 0 d x

\int 0 d x = c_{1}

y = c_{1}

l a pl a ce t r an s f or m 4 e^{- 7 t} cos (9 t)

\int_{- \infty}^{0} \frac{1}{2 - 9 x} d x

\frac{d}{d x} (3 x^{2} + 9 x + 2)

\int \frac{e ^{x + 3}}{x + 3} d x

a re a y = - \frac{1}{2} x^{2} + 2, y = 0

What is the solution for (dy)/(dx)(xsqrt(16-x))=0 ?
The solution for (dy)/(dx)(xsqrt(16-x))=0 is y=c_{1}