y^'=((y^2-1))/(2x),y(1)=-2

Lösung

y^{^{'}} = \frac{( y ^{2} - 1 )}{2 x}, y (1) = - 2

y = - \frac{1}{3 x - 1} - \frac{3 x}{3 x - 1}

Schritte zur Lösung

y^{'} (x) = \frac{( y ^{2} - 1 )}{2 x}

Solve linear ODE:

y = - \frac{1}{3 x - 1} - \frac{3 x}{3 x - 1}

y = - \frac{1}{3 x - 1} - \frac{3 x}{3 x - 1}

\frac{d y}{d t} = - \frac{3 y}{t} - 2 - t^{- 4}, y (1) = 4

x \to 2 lim (x)

a re a x, x^{3}, 4 x, 0

\int_{0}^{1} \frac{4 x}{e ^{x^{2}}} d x

\frac{\partial}{\partial x} ((x^{2} + y^{2} + z^{2})^{0.5})