What is the tangent of y=-5-8x^2,(-3,-77) ?

The tangent of y=-5-8x^2,(-3,-77) is y=48x+67

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tangent of y=-5-8x^2,(-3,-77)

tangent of

y = - 5 - 8 x^{2}, (- 3, - 77)

y = 48 x + 67

Solution steps

Find the slope of

y = - 5 - 8 x^{2} : \frac{d y}{d x} = - 16 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 48

Find the line with slope m=

48

and passing through

(- 3, - 77) : y = 48 x + 67

y = 48 x + 67

x \frac{d y}{d x} + y = 11 x

\int e^{- \frac{x}{3}} d x

(4, 3), (- 2, 9)

\frac{d}{d x} (\frac{x ^{2} - x}{x ^{3} + x + 1})

\int 1 - 64 x^{2} d x

What is the tangent of y=-5-8x^2,(-3,-77) ?
The tangent of y=-5-8x^2,(-3,-77) is y=48x+67