What is the integral of (3^2+x^{12}) ?

The integral of (3^2+x^{12}) is 9x+(x^{13})/(13)+C

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integral of (3^2+x^{12})

\int (3^{2} + x^{12}) d x

9 x + \frac{x ^{13}}{13} + C

Solution steps

\int 3^{2} + x^{12} d x

Simplify

= \int 9 + x^{12} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 d x + \int x^{12} d x

\int 9 d x = 9 x

\int x^{12} d x = \frac{x ^{13}}{13}

= 9 x + \frac{x ^{13}}{13}

Add a constant to the solution

= 9 x + \frac{x ^{13}}{13} + C

\frac{d}{d x} (x \cdot (ln (x))^{2})

in v erse l a pl a ce \frac{1}{s ( s ^{2} + 4 s + 3 )}

\int 12 x^{\frac{1}{2}} d x

\frac{d}{d x} (lo g_{e} (\frac{1}{x}))

d er i v a t i v e f (x) = x^{2} + x - 3

What is the integral of (3^2+x^{12}) ?
The integral of (3^2+x^{12}) is 9x+(x^{13})/(13)+C