What is the derivative of 4/((x+3^2)) ?

The derivative of 4/((x+3^2)) is -8/((x+3)^3)

What is the first derivative of 4/((x+3^2)) ?

The first derivative of 4/((x+3^2)) is -8/((x+3)^3)

\frac{d}{d x} (\frac{4}{( x + 3 ) ^{2}})

- \frac{8}{( x + 3 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{4}{( x + 3 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{( x + 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x + 3)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 3 ) ^{3}} \frac{d}{d x} (x + 3)

= - \frac{2}{( x + 3 ) ^{3}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= 4 (- \frac{2}{( x + 3 ) ^{3}} \cdot 1)

Simplify

4 (- \frac{2}{( x + 3 ) ^{3}} \cdot 1) : - \frac{8}{( x + 3 ) ^{3}}

= - \frac{8}{( x + 3 ) ^{3}}

\frac{\partial}{\partial x} (2 - x^{2} + y^{2})

t an g e n t \frac{1}{3 x}

a re a y = sin (2 x), y = cos (2 x), x = 0, x = \frac{π}{4}

l o n g d i v i s i o n \frac{4 x ^{2} - 3}{x - 1}

t an g e n t \frac{2}{3 x + 5}

What is the derivative of 4/((x+3^2)) ?
The derivative of 4/((x+3^2)) is -8/((x+3)^3)
What is the first derivative of 4/((x+3^2)) ?
The first derivative of 4/((x+3^2)) is -8/((x+3)^3)