fläche x^3,-x,8

Lösung

fläche

x^{3}, - x, 8

44

Schritte zur Lösung

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

x^{3} = - x : x = 0

x^{3} = 8 : x = 2

- x = 8 : x = - 8

= \int_{- 8}^{0} ∣ f_{2} (x) - f_{3} (x) ∣ d x + \int_{0}^{2} ∣ f_{1} (x) - f_{3} (x) ∣ d x

= \int_{- 8}^{0} ∣ - x - 8 ∣ d x + \int_{0}^{2} x^{3} - 8 d x

\int_{- 8}^{0} ∣ - x - 8 ∣ d x = 32

\int_{0}^{2} x^{3} - 8 d x = 12

= 32 + 12

Vereinfache

= 44

\int_{0}^{6} 9 4 x + 1 d x

36 y^{^{''}} - y = 0, y (- 5) = 1, y^{^{'}} (- 5) = - 1

y^{^{''}} - y^{^{'}} = 0

x \to 2 + lim (tan (\frac{π x}{4}))

\int_{1}^{\infty} 2^{- x} d x