What is the derivative of 2x^3+4 ?

The derivative of 2x^3+4 is 6x^2

What is the first derivative of 2x^3+4 ?

The first derivative of 2x^3+4 is 6x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (2 x^{3} + 4)

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4) = 0

= 6 x^{2} + 0

Simplify

= 6 x^{2}

\int x + \frac{1}{x ^{2} + 1} d x

\frac{d}{d x} (e^{x} (x - 3))

a re a x, \frac{1}{2} x, 9

x \to - 1 + lim (2 x^{3} - 2 m)

d er i v a t i v e f (x) = 5 e^{2 x}