What is the tangent of f(x)=6e^{-0.6x},\at x=4 ?

The tangent of f(x)=6e^{-0.6x},\at x=4 is y=-0.32658…x+6/(e^{2.4)}+1.30633…

tangent of f(x)=6e^{-0.6x},\at x=4

tangent of

f (x) = 6 e^{- 0.6 x}, at x = 4

y = - 0.32658 \dots x + \frac{6}{e ^{2.4}} + 1.30633 \dots

Solution steps

Find the tangent point:

(4, \frac{6}{e ^{2.4}})

Find the slope of

f (x) = 6 e^{- 0.6 x} : \frac{df ( x )}{d x} = - 3.6 e^{- 0.6 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 0.32658 \dots

Find the line with slope m=

- 0.32658 \dots

and passing through

(4, \frac{6}{e ^{2.4}}) : y = - 0.32658 \dots x + \frac{6}{e ^{2.4}} + 1.30633 \dots

y = - 0.32658 \dots x + \frac{6}{e ^{2.4}} + 1.30633 \dots

\int (y - 1) d y

\frac{\partial}{\partial x} (x e^{4 x})

a re a 2 x = y, x + y = 4, x + y = 12

\int \frac{( 3 x ^{2} + 2 x - 3 )}{x ^{3} - x} d x

d er i v a t i v e t^{2} e^{- t} + (ln (t))^{2}

What is the tangent of f(x)=6e^{-0.6x},\at x=4 ?
The tangent of f(x)=6e^{-0.6x},\at x=4 is y=-0.32658…x+6/(e^{2.4)}+1.30633…