integral of (9(x-9))/((x+5)(x-2))

Lösung

\int \frac{9 ( x - 9 )}{( x + 5 ) ( x - 2 )} d x

9 (2 ln ∣ x + 5 ∣ - ln ∣ x - 2 ∣) + C

Schritte zur Lösung

\int \frac{9 ( x - 9 )}{( x + 5 ) ( x - 2 )} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{x - 9}{( x + 5 ) ( x - 2 )} d x

Ermittle den Partialbruch von

\frac{x - 9}{( x + 5 ) ( x - 2 )} : \frac{2}{x + 5} - \frac{1}{x - 2}

= 9 \cdot \int \frac{2}{x + 5} - \frac{1}{x - 2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9 (\int \frac{2}{x + 5} d x - \int \frac{1}{x - 2} d x)

\int \frac{2}{x + 5} d x = 2 ln ∣ x + 5 ∣

\int \frac{1}{x - 2} d x = ln ∣ x - 2 ∣

= 9 (2 ln ∣ x + 5 ∣ - ln ∣ x - 2 ∣)

Füge eine Konstante zur Lösung hinzu

= 9 (2 ln ∣ x + 5 ∣ - ln ∣ x - 2 ∣) + C

\frac{d}{d x} ((\frac{4 x ^{2}}{2 - x})^{3})

\int_{0}^{2} (2 - x)^{2} d x

d er i v a t i v e cos (x)

a re a 3 x^{2}, 18 x - 6 x^{2}

\int_{1}^{3} 2 x^{2} - 2 x + 3 d x