y^'=((x^2+y^2))/(xy)

Lösung

y^{^{'}} = \frac{( x ^{2} + y ^{2} )}{x y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{( x ^{2} + y ^{2} )}{x y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

d er i v a t i v e x^{2} f (x^{2} + 2 x)

\frac{\partial}{\partial y} (3 x cos (y))

\int \frac{21}{x ( x ^{2} + 4 ) ^{2}} d x

\frac{d}{d x} (ln (\frac{( x + 2 )}{x ^{2}}))

x \to 1 + lim (\frac{1}{1 - x ^{2}})