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tangent f(x)=(x^2-48)^4,\at x=7

解答

切线

f (x) = (x^{2} - 48)^{4}, at x = 7

解答

y = 56 x - 391

求解步骤

找到切点:

(7, 1)

计算

f (x) = (x^{2} - 48)^{4}

的斜率:

\frac{df ( x )}{d x} = 8 x (x^{2} - 48)^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 56

找到斜率 m=

56

且穿过

(7, 1)

的直线:

y = 56 x - 391

y = 56 x - 391

作图

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