(\partial)/(\partial x)(-7(x+2y)^5)

解答

\frac{\partial}{\partial x} (- 7 (x + 2 y)^{5})

- 35 (x + 2 y)^{4}

求解步骤

\frac{\partial}{\partial x} (- 7 (x + 2 y)^{5})

将

y

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= - 7 \frac{\partial}{\partial x} ((x + 2 y)^{5})

使用连锁律:

5 (x + 2 y)^{4} \frac{\partial}{\partial x} (x + 2 y)

= 5 (x + 2 y)^{4} \frac{\partial}{\partial x} (x + 2 y)

\frac{\partial}{\partial x} (x + 2 y) = 1

= - 7 \cdot 5 (x + 2 y)^{4} \cdot 1

化简

= - 35 (x + 2 y)^{4}

\frac{d ^{2}}{d x ^{2}} (\frac{2}{1 + x ^{2}})

\frac{d}{d x} (- x + 1)

\int π^{x} - x^{- 1} d x

\int_{7}^{14} - 30 x^{2} + 340 x d x

x \to i lim (\frac{x ^{4} - 1}{x - i})