(x+y)^2dx+(2xy+x^2-1)dy=0

Lösung

(x + y)^{2} d x + (2 x y + x^{2} - 1) d y = 0

y = \frac{3 - 3 x ^{2} + 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}, y = \frac{3 - 3 x ^{2} - 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}

Schritte zur Lösung

(x + y)^{2} d x + (2 x y + x^{2} - 1) d y = 0

Solve exact ODE:

y = \frac{3 - 3 x ^{2} + 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}, y = \frac{3 - 3 x ^{2} - 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}

y = \frac{3 - 3 x ^{2} + 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}, y = \frac{3 - 3 x ^{2} - 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}

d er i v a t i v e f (x) = 2^{50}

\int x (1 - x)^{7} d x

t an g e n t f (x) = 3 x^{3} + 3 x^{2} - 11 x - 1

y^{^{''}} + 9 y = 3 csc^{2} (3 t)

\int sinh (2 x) d x