integral of 3+4x

Lösung

\int 3 + 4 x d x

3 x + 2 x^{2} + C

Schritte zur Lösung

\int 3 + 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d x + \int 4 x d x

\int 3 d x = 3 x

\int 4 x d x = 2 x^{2}

= 3 x + 2 x^{2}

Füge eine Konstante zur Lösung hinzu

= 3 x + 2 x^{2} + C

\int \frac{1}{x ^{4} 4 - x ^{2}} d x

\int \frac{e ^{5 x}}{5} d x

\int_{0}^{1} \frac{2 x}{( x ^{2} + 3 ) ^{2}} d x

t an g e n t f (x) = \frac{- 9 x ^{2}}{2} + 7 x + 2

\frac{\partial}{\partial y} (arctan (x^{4} y^{3}))