(\partial)/(\partial x)(3cos(2x))

Lösung

\frac{\partial}{\partial x} (3 cos (2 x))

- 6 sin (2 x)

Schritte zur Lösung

\frac{\partial}{\partial x} (3 cos (2 x))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (cos (2 x))

Wende die Kettenregel an:

- sin (2 x) \frac{\partial}{\partial x} (2 x)

= - sin (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= 3 (- sin (2 x) \cdot 2)

Vereinfache

= - 6 sin (2 x)

d er i v a t i v e h (x) = \frac{1}{x ^{2}} + \frac{1}{x} + x

\int \frac{cos ( a x )}{b - a sin ( a x )} d x

x \to 5 lim (3 x + 6)

\frac{d}{d x} (arcsin (\frac{x}{1 - x}))

\int \frac{x}{x ^{2}} d x