x^'=x^2,x(0)=1

Lösung

x^{^{'}} = x^{2}, x (0) = 1

x = - \frac{1}{t - 1}

Schritte zur Lösung

x^{'} (t) = x^{2}

Solve separable ODE:

x = - \frac{1}{t - 1}

x = - \frac{1}{t - 1}

n = 0 \sum \infty (\frac{1}{2})^{2 n + 1}

d er i v a t i v e \frac{1}{x + \frac{1}{x}}

x \to + (- 0) lim (f (x))

\frac{d}{d x} (cos (2 x) - sin (x))

\int_{1}^{16} \frac{x - 7}{x} d x