What is the derivative of 3/(4x^2) ?

The derivative of 3/(4x^2) is -3/(2x^3)

What is the first derivative of 3/(4x^2) ?

The first derivative of 3/(4x^2) is -3/(2x^3)

\frac{d}{d x} (\frac{3}{4 x ^{2}})

- \frac{3}{2 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{3}{4 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{4} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{3}{4} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{4} (- 2 x^{- 2 - 1})

Simplify

\frac{3}{4} (- 2 x^{- 2 - 1}) : - \frac{3}{2 x ^{3}}

= - \frac{3}{2 x ^{3}}

t an g e n t f (x) = x^{4} - 13 x^{2} + 36

\int_{0}^{1} \frac{45}{x ^{5}} d x

d er i v a t i v e (1 + \frac{4}{x})^{x}

\frac{\partial}{\partial x} (2 e^{x - 2} - y)

d er i v a t i v e f (x) = \frac{- x ^{2} - 1}{( x ^{2} + 1 ) ^{2}}

What is the derivative of 3/(4x^2) ?
The derivative of 3/(4x^2) is -3/(2x^3)
What is the first derivative of 3/(4x^2) ?
The first derivative of 3/(4x^2) is -3/(2x^3)