y^'= y/x+x/y

Lösung

y^{^{'}} = \frac{y}{x} + \frac{x}{y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{y}{x} + \frac{x}{y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y^{^{''}} + y^{^{'}} = sin (20 x)

\frac{d y}{d x} = \frac{1}{10} y cos^{2} (y)

\frac{d}{d x} (\frac{x ^{2} + 32 x}{8})

\int_{0}^{1} 2 π (2 - y) (2 y^{2}) d y

\int_{2}^{3} \frac{1}{x ^{2}} d x