y^'-3y= y/x

Lösung

y^{^{'}} - 3 y = \frac{y}{x}

y = e^{3 x + c_{1}} x

Schritte zur Lösung

y^{'} (x) - 3 y = \frac{y}{x}

Solve separable ODE:

y = e^{3 x + c_{1}} x

y = e^{3 x + c_{1}} x

\int 6 x^{2} - 4 x d x

\frac{d}{d x} (- \frac{4 e ^{\frac{4}{x}}}{x ^{2}})

\frac{\partial}{\partial x} (- 2 e^{x} ln (y))

\int (\frac{6}{5 x ^{2}} - 1) d x

x \to 0 lim ((1 + 6 x)^{\frac{4}{x}})