What is the derivative of g(x)=(1-3x) ?

The derivative of g(x)=(1-3x) is -3

What is the first derivative of g(x)=(1-3x) ?

The first derivative of g(x)=(1-3x) is -3

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derivative of

g (x) = (1 - 3 x)

- 3

Solution steps

\frac{d}{d x} ((1 - 3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (3 x)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 x) = 3

= 0 - 3

Simplify

= - 3

\frac{\partial}{\partial x} (x^{4} + y^{4} - 32 x + 4 y + 4)

y^{^{'}} + \frac{1}{t} y = 3 cos (2 t)

\frac{d}{d x} (x^{2} cos (ln (x)))

x \to 0 + lim (x \cdot e^{\frac{1}{x}})

\int \frac{x}{1 - 3 x ^{2}} d x

What is the derivative of g(x)=(1-3x) ?
The derivative of g(x)=(1-3x) is -3
What is the first derivative of g(x)=(1-3x) ?
The first derivative of g(x)=(1-3x) is -3