y^'+1/(x+1)y=x^{-2}

Lösung

y^{^{'}} + \frac{1}{x + 1} y = x^{- 2}

y = \frac{ln ( x )}{x + 1} - \frac{1}{x ( x + 1 )} + \frac{c _{1}}{x + 1}

Schritte zur Lösung

y^{'} (x) + \frac{1}{x + 1} y = x^{- 2}

Solve linear ODE:

y = \frac{ln ( x )}{x + 1} - \frac{1}{x ( x + 1 )} + \frac{c _{1}}{x + 1}

y = \frac{ln ( x )}{x + 1} - \frac{1}{x ( x + 1 )} + \frac{c _{1}}{x + 1}

t an g e n t f (x) = (3 x - 2) (x + 4), (1, 5)

\frac{\partial}{\partial y} (x \cdot cos (y) \cdot sin (z))

x \to \infty lim (\frac{- x}{x})

\int \frac{( 3 x - 5 )}{x ^{2} + 4 x} d x

d er i v a t i v e f (x) = 3 x^{2} - 7