y^'=-y^2t-y^2t^2,y(0)=3

Lösung

y^{^{'}} = - y^{2} t - y^{2} t^{2}, y (0) = 3

y = \frac{6}{2 t ^{3} + 3 t ^{2} + 2}

Schritte zur Lösung

y^{'} (t) = - y^{2} t - y^{2} t^{2}

Solve separable ODE:

y = \frac{6}{2 t ^{3} + 3 t ^{2} + 2}

y = \frac{6}{2 t ^{3} + 3 t ^{2} + 2}

x \to \frac{1}{2} - lim (\frac{1}{2 x - 1})

\frac{d}{d x} (ln (\frac{x ^{2}}{x + 1}))

d er i v a t i v e f (x) = (3 a + 1)^{2}

x \to + 6 lim (36 - x^{2})

x \to + 1 lim (e^{x^{2} - x})