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Popular Calculus >

y^'=x(y+1)

Solution

y^{^{'}} = x (y + 1)

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Solution steps

y^{'} (x) = x (y + 1)

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Graph

Popular Examples

integral of 1/(25+3x^2)

\int \frac{1}{25 + 3 x ^{2}} d x

integral of 1/(x^2sqrt(16x^2-9))

\int \frac{1}{x ^{2} 16 x ^{2} - 9} d x

(\partial)/(\partial x)(1+x)

\frac{\partial}{\partial x} (1 + x)

(dv)/(dx)=-2v-32

\frac{d v}{d x} = - 2 v - 32

(\partial)/(\partial y)(cos(x)y)

\frac{\partial}{\partial y} (cos (x) y)

Frequently Asked Questions (FAQ)

What is the solution for y^'=x(y+1) ?
The solution for y^'=x(y+1) is y=e^{(x^2)/2+c_{1}}-1