What is the integral of (x+2)/(sqrt(x^2+4)) ?

The integral of (x+2)/(sqrt(x^2+4)) is sqrt(x^2+4)+2ln(1/2 |x+sqrt(4+x^2)|)+C

integral of (x+2)/(sqrt(x^2+4))

\int \frac{x + 2}{x ^{2} + 4} d x

x^{2} + 4 + 2 ln (\frac{1}{2} x + 4 + x^{2}) + C

Solution steps

\int \frac{x + 2}{x ^{2} + 4} d x

Expand

\frac{x + 2}{x ^{2} + 4} : \frac{x}{x ^{2} + 4} + \frac{2}{x ^{2} + 4}

= \int \frac{x}{x ^{2} + 4} + \frac{2}{x ^{2} + 4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 4} d x + \int \frac{2}{x ^{2} + 4} d x

\int \frac{x}{x ^{2} + 4} d x = x^{2} + 4

\int \frac{2}{x ^{2} + 4} d x = 2 ln (\frac{1}{2} x + 4 + x^{2})

= x^{2} + 4 + 2 ln (\frac{1}{2} x + 4 + x^{2})

Add a constant to the solution

= x^{2} + 4 + 2 ln (\frac{1}{2} x + 4 + x^{2}) + C

t an g e n t f (x) = \frac{2}{x}, at x = - 2

y^{^{''}} + y = 2^{x}

\int_{1}^{3} (x^{5} + \frac{1}{4 x ^{5}}) d x

t an g e n t f (x) = \frac{3}{x}, (- 5, - \frac{3}{5})

n = 0 \sum \infty sin (\frac{1}{n})

What is the integral of (x+2)/(sqrt(x^2+4)) ?
The integral of (x+2)/(sqrt(x^2+4)) is sqrt(x^2+4)+2ln(1/2 |x+sqrt(4+x^2)|)+C