斜率 (sqrt(3x+1))(8.5)

解答

斜率

(3 x + 1) (8.5)

\frac{12.75}{3 x + 1}

求解步骤

y = 3 x + 1 \cdot 8.5

要确定函数的斜率，对

3 x + 1 8.5

求导

\frac{d}{d x} (3 x + 1 \cdot 8.5) = \frac{12.75}{3 x + 1}

\frac{12.75}{3 x + 1}

\int_{- 1}^{2} x + 2 d x

a re a y = \frac{3}{x}, y = 12 x, y = \frac{1}{12 x}

\int \frac{2 x}{x ^{2} + 4 x + 12} d x

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\frac{d}{d x} (ln (\frac{3 + e ^{x}}{3 - e ^{x}}))