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Beliebt Rechnen >

y^{''}+8y^'+41y=0,y(0)=2,y^'(0)=-7

Lösung

y^{^{''}} + 8 y^{^{'}} + 41 y = 0, y (0) = 2, y^{^{'}} (0) = - 7

Lösung

y = e^{- 4 t} (2 cos (5 t) + \frac{1}{5} sin (5 t))

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 41 y = 0

Solve linear ODE:

y = e^{- 4 t} (2 cos (5 t) + \frac{1}{5} sin (5 t))

y = e^{- 4 t} (2 cos (5 t) + \frac{1}{5} sin (5 t))

Graph

Beliebte Beispiele

integral from-1 to 1 of 1/(x^{2/3)}

\int_{- 1}^{1} \frac{1}{x ^{\frac{2}{3}}} d x

derivative of ((x+1/x)^3)

\frac{d}{d x} ((\frac{x + 1}{x})^{3})

derivative of (x^2/(x^2-16))

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 16})

tangent f(x)=(13x-1)^{-1/3},\at x=5

t an g e n t f (x) = (13 x - 1)^{- \frac{1}{3}}, at x = 5

derivative t/((t-9)^2)

d er i v a t i v e \frac{t}{( t - 9 ) ^{2}}