(cos(ln(x)))^'

解答

(cos (ln (x)))^{^{'}}

- \frac{sin ( ln ( x ) )}{x}

求解步骤

(cos (ln (x)))^{'}

使用连锁律:

- sin (ln (x)) (ln (x))^{'}

= - sin (ln (x)) (ln (x))^{'}

(ln (x))^{'} = \frac{1}{x}

= - sin (ln (x)) \frac{1}{x}

化简

- sin (ln (x)) \frac{1}{x} : - \frac{sin ( ln ( x ) )}{x}

= - \frac{sin ( ln ( x ) )}{x}

\frac{d}{d x} (a r (x) c)

d er i v a t i v e 2 sin (x) + sin^{2} (x)

\frac{\partial}{\partial t} (y + x cos (t))

\int 9 x^{2} d x

d er i v a t i v e y = (2 tan^{2} (2 x) - 1)^{\frac{1}{2}}