y^'=y(xy^4+5)

Lösung

y^{^{'}} = y (x y^{4} + 5)

y = 4 \frac{100 e ^{20 x}}{- 20 x e ^{20 x} + e ^{20 x} + c _{1}}, y = - 4 \frac{100 e ^{20 x}}{- 20 x e ^{20 x} + e ^{20 x} + c _{1}}

Schritte zur Lösung

y^{'} (x) = y (x y^{4} + 5)

Solve Bernoulli ODE:

y = 4 \frac{100 e ^{20 x}}{- 20 x e ^{20 x} + e ^{20 x} + c _{1}}, y = - 4 \frac{100 e ^{20 x}}{- 20 x e ^{20 x} + e ^{20 x} + c _{1}}

y = 4 \frac{100 e ^{20 x}}{- 20 x e ^{20 x} + e ^{20 x} + c _{1}}, y = - 4 \frac{100 e ^{20 x}}{- 20 x e ^{20 x} + e ^{20 x} + c _{1}}

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