0.1y^'-0.1y=0

Lösung

0.1 y^{^{'}} - 0.1 y = 0

y = e^{t + c_{1}}

Schritte zur Lösung

0.1 y^{'} (t) - 0.1 y = 0

Solve separable ODE:

y = e^{t + c_{1}}

y = e^{t + c_{1}}

t an g e n t f (x) = sin (x^{2})

\int_{1}^{2} \frac{x ^{6} + 4 x ^{8}}{x ^{5}} d x

\int x^{2} + 6 x + 2 d x

\frac{\partial}{\partial x} (x + 1 + 1)

\frac{\partial}{\partial x} (x^{2} y^{2} z)