d/(dy)(sqrt(tan(x)+y))

解答

\frac{d}{d y} (tan (x) + y)

\frac{1}{2 tan ( x ) + y}

求解步骤

\frac{d}{d y} (tan (x) + y)

将

x

视为常数

使用连锁律:

\frac{1}{2 tan ( x ) + y} \frac{d}{d y} (tan (x) + y)

= \frac{1}{2 tan ( x ) + y} \frac{d}{d y} (tan (x) + y)

\frac{d}{d y} (tan (x) + y) = 1

= \frac{1}{2 tan ( x ) + y} \cdot 1

化简

= \frac{1}{2 tan ( x ) + y}

\frac{d}{d x} (x^{\frac{- 1}{2}})

in v erse l a pl a ce \frac{1}{( s - 4 )}

\frac{\partial}{\partial y} (x^{2} yz + \frac{1}{x y z ^{2}})

\frac{d y}{d x} = 5 y^{2}, y (0) = 3

t an g e n t f (x) = x^{3} - 15 x, (1, - 14)