integral from 1 to 3 of (x^2+2x-4)

Lösung

\int_{1}^{3} (x^{2} + 2 x - 4) d x

\frac{26}{3}

Dezimale

8.66666 \dots

Schritte zur Lösung

\int_{1}^{3} x^{2} + 2 x - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x + \int_{1}^{3} 2 x d x - \int_{1}^{3} 4 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 2 x d x = 8

\int_{1}^{3} 4 d x = 8

= \frac{26}{3} + 8 - 8

Vereinfache

= \frac{26}{3}

n = 1 \sum \infty \frac{5 ^{n}}{3 ^{n}}

\int \frac{1}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} d x

3 y^{^{''}} - 24 y^{^{'}} + 36 y = 6 sin (2 x)

\int_{1}^{3} \frac{2}{4 + ( x - 1 ) ^{2}} d x

y^{^{'}} = \frac{2 y}{x}