derivative x=4t^2-3t+11

解答

导数

x = 4 t^{2} - 3 t + 11

8 t - 3

求解步骤

\frac{d}{d t} (4 t^{2} - 3 t + 11)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4 t^{2}) - \frac{d}{d t} (3 t) + \frac{d}{d t} (11)

\frac{d}{d t} (4 t^{2}) = 8 t

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (11) = 0

= 8 t - 3 + 0

化简

= 8 t - 3

\frac{d}{d x} (sin^{2} (x) + sin (x))

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