integral of (9x^2+6x)

Lösung

\int (9 x^{2} + 6 x) d x

3 x^{3} + 3 x^{2} + C

Schritte zur Lösung

\int 9 x^{2} + 6 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{2} d x + \int 6 x d x

\int 9 x^{2} d x = 3 x^{3}

\int 6 x d x = 3 x^{2}

= 3 x^{3} + 3 x^{2}

Füge eine Konstante zur Lösung hinzu

= 3 x^{3} + 3 x^{2} + C

d er i v a t i v e y = 3 t + 2 t^{3}

\int_{0}^{3} \frac{1}{( x - 1 ) ^{2}} d x

a re a y = 6 x - x^{2}, y = 2 x

x \to 0 lim (\frac{1}{x} ln (1 - 6 x))

\frac{d y}{d x} = 2.5 - \frac{5 y}{2 x + 100}