y^'+2y=2e^x

Lösung

y^{^{'}} + 2 y = 2 e^{x}

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

Schritte zur Lösung

y^{'} (x) + 2 y = 2 e^{x}

Solve linear ODE:

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

\int \frac{x ^{4} + 2}{x ^{3} - x ^{2}} d x

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n = 1 \sum \infty (\frac{1}{2})^{2 n}

x \to 2 + lim (\frac{x ^{2}}{4 - x ^{2}})

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