4y^{''}+2y^'+4y=100

Lösung

4 y^{^{''}} + 2 y^{^{'}} + 4 y = 100

y = e^{- \frac{t}{4}} (c_{1} cos (\frac{15 t}{4}) + c_{2} sin (\frac{15 t}{4})) + 25

Schritte zur Lösung

4 y^{''} (t) + 2 y^{'} (t) + 4 y = 100

Solve linear ODE:

y = e^{- \frac{t}{4}} (c_{1} cos (\frac{15 t}{4}) + c_{2} sin (\frac{15 t}{4})) + 25

y = e^{- \frac{t}{4}} (c_{1} cos (\frac{15 t}{4}) + c_{2} sin (\frac{15 t}{4})) + 25

s l o p e (5) (7.5)

t an g e n t f (x) = \frac{2 x - 1}{2 x + 1}, (- 1, 3)

\int \frac{z ^{2}}{y} d y

in v erse l a pl a ce \frac{( s + 1 )}{s ^{2} + s + 10}

\frac{d}{d x} (ln (\frac{x ^{3} + 4}{2 x}))