y^{''}+y=(cot(x))^2

解

y^{^{''}} + y = (cot (x))^{2}

y = c_{1} cos (x) + c_{2} sin (x) + (- ln (tan (\frac{x}{2})) - cos (x)) cos (x) + (- csc (x) - sin (x)) sin (x)

解答ステップ

y^{''} (x) + y = (cot (x))^{2}

線形 ODE を解く:

y = c_{1} cos (x) + c_{2} sin (x) + (- ln (tan (\frac{x}{2})) - cos (x)) cos (x) + (- csc (x) - sin (x)) sin (x)

y = c_{1} cos (x) + c_{2} sin (x) + (- ln (tan (\frac{x}{2})) - cos (x)) cos (x) + (- csc (x) - sin (x)) sin (x)