sum from n=1 to infinity of ln^n(3)

解答

n = 1 \sum \infty ln^{n} (3)

发散

求解步骤

n = 1 \sum \infty ln^{n} (3)

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty ln^{n} (3) - ln^{0} (3)

n = 0 \sum \infty ln^{n} (3) =

发散

如果表达式有部分发散，则整个表达式发散

= 发散

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