What is the solution for (dy)/(dx)=(x^2y^2)/(1+x) ?

The solution for (dy)/(dx)=(x^2y^2)/(1+x) is y=-2/(x^2-2x+2ln(1+x)-3+c_{1)}

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(dy)/(dx)=(x^2y^2)/(1+x)

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + x}

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + x}

Solve separable ODE:

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

\int_{0}^{5} 2 x^{2} e^{- x} d x

d er i v a t i v e 3 t (2 t^{2} - 5)^{4}

in v erse l a pl a ce \frac{( s - 2 )}{( s - 2 ) ^{2} + 1}

\frac{\partial}{\partial x} (e^{2 x + y})

t an g e n t f (x) = 7 x - 6 x, at x = 1

What is the solution for (dy)/(dx)=(x^2y^2)/(1+x) ?
The solution for (dy)/(dx)=(x^2y^2)/(1+x) is y=-2/(x^2-2x+2ln(1+x)-3+c_{1)}