What is the derivative of 4/(\sqrt[3]{x}) ?

The derivative of 4/(\sqrt[3]{x}) is -4/(3x^{4/3)}

What is the first derivative of 4/(\sqrt[3]{x}) ?

The first derivative of 4/(\sqrt[3]{x}) is -4/(3x^{4/3)}

\frac{d}{d x} (\frac{4}{3 x})

- \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (\frac{4}{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{3 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} (x^{- \frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- \frac{1}{3} x^{- \frac{1}{3} - 1})

Simplify

4 (- \frac{1}{3} x^{- \frac{1}{3} - 1}) : - \frac{4}{3 x ^{\frac{4}{3}}}

= - \frac{4}{3 x ^{\frac{4}{3}}}

d er i v a t i v e f (x) = - x + \frac{6}{x} + 1

in v erse l a pl a ce \frac{s - 1}{s ^{2} - 2 s + 5}

\int \frac{4}{t} d t

t an g e n t y = x^{3} - 6 x^{2} + 7 x + 3

\int \frac{( e ^{x} - e ^{- x} )}{e ^{x} + e ^{- x}} d x

What is the derivative of 4/(\sqrt[3]{x}) ?
The derivative of 4/(\sqrt[3]{x}) is -4/(3x^{4/3)}
What is the first derivative of 4/(\sqrt[3]{x}) ?
The first derivative of 4/(\sqrt[3]{x}) is -4/(3x^{4/3)}