(1/(x^4))^'

Lösung

(\frac{1}{x ^{4}})^{^{'}}

- \frac{4}{x ^{5}}

Schritte zur Lösung

(\frac{1}{x ^{4}})^{'}

Wende Exponentenregel an:

\frac{1}{a} = a^{- 1}

= (x^{- 4})^{^{'}}

Wende die Potenzregel an:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 4 x^{- 4 - 1}

Vereinfache

- 4 x^{- 4 - 1} : - \frac{4}{x ^{5}}

= - \frac{4}{x ^{5}}

\frac{\partial}{\partial x} (4 - x^{4} + 2 x^{2} - y^{2})

\frac{\partial}{\partial x} (4 x - 2 y^{2} + z^{2})

\frac{d}{d x} (9 e^{x} + \frac{4}{3 x})

x \to 6 lim (\frac{x - 3}{x - 1})

\frac{\partial}{\partial x} (2 e^{- 2 x} + \frac{1}{3} e^{x})