What is the integral from 2 to infinity of 1/(x^5) ?

The integral from 2 to infinity of 1/(x^5) is 1/64

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integral from 2 to infinity of 1/(x^5)

\int_{2}^{\infty} \frac{1}{x ^{5}} d x

\frac{1}{64}

Decimal

0.015625

Solution steps

\int_{2}^{\infty} \frac{1}{x ^{5}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{5}} d x = - \frac{1}{4 x ^{4}} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{1}{x ^{5}} d x = 0 - (- \frac{1}{64})

= 0 - (- \frac{1}{64})

Simplify

= \frac{1}{64}

\int x e^{\frac{x ^{2}}{2}} d x

x \to π lim (3 arctan (x))

d er i v a t i v e \frac{x ^{2} - 1}{x + 3}

\frac{\partial}{\partial y} (x^{3})

(x^{4} + y^{4}) d x - x y^{3} d y = 0

What is the integral from 2 to infinity of 1/(x^5) ?
The integral from 2 to infinity of 1/(x^5) is 1/64