(\partial)/(\partial x)(ln(7x^2+xy))

Lösung

\frac{\partial}{\partial x} (ln (7 x^{2} + x y))

\frac{14 x + y}{7 x ^{2} + x y}

Schritte zur Lösung

\frac{\partial}{\partial x} (ln (7 x^{2} + x y))

Behandle

y

als Konstante

Wende die Kettenregel an:

\frac{1}{7 x ^{2} + x y} \frac{\partial}{\partial x} (7 x^{2} + x y)

= \frac{1}{7 x ^{2} + x y} \frac{\partial}{\partial x} (7 x^{2} + x y)

\frac{\partial}{\partial x} (7 x^{2} + x y) = 14 x + y

= \frac{1}{7 x ^{2} + x y} (14 x + y)

Vereinfache

\frac{1}{7 x ^{2} + x y} (14 x + y) : \frac{14 x + y}{7 x ^{2} + x y}

= \frac{14 x + y}{7 x ^{2} + x y}

y^{^{''}} + 3 y^{^{'}} + 2 y = cos (e x)

\int \frac{9 x ^{2}}{2} - 5 cos (x) + 7 d x

in v erse l a pl a ce - \frac{1}{s ^{2}}

\frac{\partial}{\partial x} (y + \frac{1}{x + y})

\frac{d}{d x} (lo g_{3} (sec (2 x)))