(\partial)/(\partial y)(4-x^2-y^2)

解

\frac{\partial}{\partial y} (4 - x^{2} - y^{2})

- 2 y

解答ステップ

\frac{\partial}{\partial y} (4 - x^{2} - y^{2})

x

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4) - \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (4) = 0

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 - 0 - 2 y

簡素化

= - 2 y