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Beliebt Rechnen >

y^'=(pi*x+y+pi^2)^2

Lösung

y^{^{'}} = (π \cdot x + y + π^{2})^{2}

Lösung

y = tan (π (x + c_{1})) π - π x - π^{2}

Schritte zur Lösung

y^{'} (x) = (π \cdot x + y + π^{2})^{2}

Solve using substitution:

y = tan (π (x + c_{1})) π - π x - π^{2}

y = tan (π (x + c_{1})) π - π x - π^{2}

Graph

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