What is the integral of-sec^2(x) ?

The integral of-sec^2(x) is -tan(x)+C

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integral of-sec^2(x)

\int - sec^{2} (x) d x

- tan (x) + C

Solution steps

\int - sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= - tan (x)

Add a constant to the solution

= - tan (x) + C

\frac{6 x}{x ^{2} + 1} (1.3)

\frac{7 x}{( x ^{3} - 2 ) ^{2}}

\int - \frac{cos ( 2 x )}{4} d x

\frac{d}{d x} ((4 x^{\frac{3}{2}} - 2 x^{\frac{1}{2}})^{3})

\int tan (2 x) sec^{5} (2 x) d x